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6x^2+18x-166=2
We move all terms to the left:
6x^2+18x-166-(2)=0
We add all the numbers together, and all the variables
6x^2+18x-168=0
a = 6; b = 18; c = -168;
Δ = b2-4ac
Δ = 182-4·6·(-168)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-66}{2*6}=\frac{-84}{12} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+66}{2*6}=\frac{48}{12} =4 $
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